Solve 3(3)^3-8(3)^2-41(3)+30

$$3 ( 3 ) ^ { 3 } - 8 ( 3 ) ^ { 2 } - 41 ( 3 ) + 30$$

Evaluate

$$-84$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 1 and 3 to get 4.

$$3^{4}-8\times 3^{2}-41\times 3+30$$

Calculate 3 to the power of 4 and get 81.

$$81-8\times 3^{2}-41\times 3+30$$

Calculate 3 to the power of 2 and get 9.

$$81-8\times 9-41\times 3+30$$

Multiply 8 and 9 to get 72.

$$81-72-41\times 3+30$$

Subtract 72 from 81 to get 9.

$$9-41\times 3+30$$

Multiply 41 and 3 to get 123.

$$9-123+30$$

Subtract 123 from 9 to get -114.

$$-114+30$$

Add -114 and 30 to get -84.

$$-84$$

Factor

$$-84$$