Solve 3(2x-3)<4x-5+3(x+3)

$$3 ( 2 x - 3 ) < 4 x - 5 + 3 ( x + 3 )$$

Solve for x

$$x>-13$$

Solution Steps

Use the distributive property to multiply 3 by 2x-3.

$$6x-9<4x-5+3\left(x+3\right)$$

Use the distributive property to multiply 3 by x+3.

$$6x-9<4x-5+3x+9$$

Combine 4x and 3x to get 7x.

$$6x-9<7x-5+9$$

Add -5 and 9 to get 4.

$$6x-9<7x+4$$

Subtract 7x from both sides.

$$6x-9-7x<4$$

Combine 6x and -7x to get -x.

$$-x-9<4$$

Add 9 to both sides.

$$-x<4+9$$

Add 4 and 9 to get 13.

$$-x<13$$

Divide both sides by -1. Since -1 is negative, the inequality direction is changed.

$$x>-13$$