Solve 3(2x-3(x+1))+8=4x-(x+3)

$$3 ( 2 x - 3 ( x + 1 ) ) + 8 = 4 x - ( x + 3 )$$

Solve for x

$$x=\frac{1}{3}\approx 0.333333333$$

Steps for Solving Linear Equation

Use the distributive property to multiply -3 by x+1.

$$3\left(2x-3x-3\right)+8=4x-\left(x+3\right)$$

Combine 2x and -3x to get -x.

$$3\left(-x-3\right)+8=4x-\left(x+3\right)$$

Use the distributive property to multiply 3 by -x-3.

$$-3x-9+8=4x-\left(x+3\right)$$

Add -9 and 8 to get -1.

$$-3x-1=4x-\left(x+3\right)$$

To find the opposite of x+3, find the opposite of each term.

$$-3x-1=4x-x-3$$

Combine 4x and -x to get 3x.

$$-3x-1=3x-3$$

Subtract 3x from both sides.

$$-3x-1-3x=-3$$

Combine -3x and -3x to get -6x.

$$-6x-1=-3$$

Add 1 to both sides.

$$-6x=-3+1$$

Add -3 and 1 to get -2.

$$-6x=-2$$

Divide both sides by -6.

$$x=\frac{-2}{-6}$$

Reduce the fraction \frac{-2}{-6} to lowest terms by extracting and canceling out -2.

$$x=\frac{1}{3}$$