Solve 3(2a-x)+ax=a^2+a

$$3 ( 2 a - x ) + a x = a ^ { 2 } + a$$

Solve for x

$$x=-\frac{a\left(5-a\right)}{a-3}$$

$$a\neq 3$$

Steps for Solving Linear Equation

Use the distributive property to multiply 3 by 2a-x.

$$6a-3x+ax=a^{2}+a$$

Subtract 6a from both sides.

$$-3x+ax=a^{2}+a-6a$$

Combine a and -6a to get -5a.

$$-3x+ax=a^{2}-5a$$

Combine all terms containing x.

$$\left(-3+a\right)x=a^{2}-5a$$

The equation is in standard form.

$$\left(a-3\right)x=a^{2}-5a$$

Divide both sides by -3+a.

$$\frac{\left(a-3\right)x}{a-3}=\frac{a\left(a-5\right)}{a-3}$$

Dividing by -3+a undoes the multiplication by -3+a.

$$x=\frac{a\left(a-5\right)}{a-3}$$

Solve for a

$$a=\frac{-\sqrt{x^{2}-2x+25}+x+5}{2}$$

$$a=\frac{\sqrt{x^{2}-2x+25}+x+5}{2}$$