Solve 3(2-x)>10

$$3 ( 2 - x ) > 10$$

Solve for x

$$x<-\frac{4}{3}$$

Solution Steps

Divide both sides by 3. Since 3 is positive, the inequality direction remains the same.

$$2-x>\frac{10}{3}$$

Subtract 2 from both sides.

$$-x>\frac{10}{3}-2$$

Convert 2 to fraction \frac{6}{3}.

$$-x>\frac{10}{3}-\frac{6}{3}$$

Since \frac{10}{3} and \frac{6}{3} have the same denominator, subtract them by subtracting their numerators.

$$-x>\frac{10-6}{3}$$

Subtract 6 from 10 to get 4.

$$-x>\frac{4}{3}$$

Divide both sides by -1. Since -1 is negative, the inequality direction is changed.

$$x<\frac{\frac{4}{3}}{-1}$$

Express \frac{\frac{4}{3}}{-1} as a single fraction.

$$x<\frac{4}{3\left(-1\right)}$$

Multiply 3 and -1 to get -3.

$$x<\frac{4}{-3}$$

Fraction \frac{4}{-3} can be rewritten as -\frac{4}{3} by extracting the negative sign.

$$x<-\frac{4}{3}$$