Solve for x
x\geq -\frac{4}{3}
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6-3x+x\leq x+10
Use the distributive property to multiply 3 by 2-x.
6-2x\leq x+10
Combine -3x and x to get -2x.
6-2x-x\leq 10
Subtract x from both sides.
6-3x\leq 10
Combine -2x and -x to get -3x.
-3x\leq 10-6
Subtract 6 from both sides.
-3x\leq 4
Subtract 6 from 10 to get 4.
x\geq -\frac{4}{3}
Divide both sides by -3. Since -3 is negative, the inequality direction is changed.
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
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Limits
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