Solve 3(2-6+4)+2(3-8-1)-(4-7+2

$$3 ( 2 - 6 + 4 ) + 2 ( 3 - 8 - 1 ) - ( 4 - 7 + 2$$

Evaluate

$$-11$$

Solution Steps

Subtract 6 from 2 to get -4.

$$3\left(-4+4\right)+2\left(3-8-1\right)-\left(4-7+2\right)$$

Add -4 and 4 to get 0.

$$3\times 0+2\left(3-8-1\right)-\left(4-7+2\right)$$

Multiply 3 and 0 to get 0.

$$0+2\left(3-8-1\right)-\left(4-7+2\right)$$

Subtract 8 from 3 to get -5.

$$0+2\left(-5-1\right)-\left(4-7+2\right)$$

Subtract 1 from -5 to get -6.

$$0+2\left(-6\right)-\left(4-7+2\right)$$

Multiply 2 and -6 to get -12.

$$0-12-\left(4-7+2\right)$$

Subtract 12 from 0 to get -12.

$$-12-\left(4-7+2\right)$$

Subtract 7 from 4 to get -3.

$$-12-\left(-3+2\right)$$

Add -3 and 2 to get -1.

$$-12-\left(-1\right)$$

The opposite of -1 is 1.

$$-12+1$$

Add -12 and 1 to get -11.

$$-11$$

Factor

$$-11$$