Solve 3(100x+10y+z)=111z

$$3 ( 100 x + 10 y + z ) = 111 z$$

Solve for x

$$x=\frac{9z}{25}-\frac{y}{10}$$

Steps for Solving Linear Equation

Use the distributive property to multiply 3 by 100x+10y+z.

$$300x+30y+3z=111z$$

Subtract 30y from both sides.

$$300x+3z=111z-30y$$

Subtract 3z from both sides.

$$300x=111z-30y-3z$$

Combine 111z and -3z to get 108z.

$$300x=108z-30y$$

Divide both sides by 300.

$$\frac{300x}{300}=\frac{108z-30y}{300}$$

Dividing by 300 undoes the multiplication by 300.

$$x=\frac{108z-30y}{300}$$

Divide 108z-30y by 300.

$$x=\frac{9z}{25}-\frac{y}{10}$$

Solve for y

$$y=\frac{18z}{5}-10x$$

Steps for Solving Linear Equation

Use the distributive property to multiply 3 by 100x+10y+z.

$$300x+30y+3z=111z$$

Subtract 300x from both sides.

$$30y+3z=111z-300x$$

Subtract 3z from both sides.

$$30y=111z-300x-3z$$

Combine 111z and -3z to get 108z.

$$30y=108z-300x$$

Divide both sides by 30.

$$\frac{30y}{30}=\frac{108z-300x}{30}$$

Dividing by 30 undoes the multiplication by 30.

$$y=\frac{108z-300x}{30}$$

Divide 108z-300x by 30.

$$y=\frac{18z}{5}-10x$$