Solve 3(1)^4+4(1)^3-5(1)^2+7(1)

$$3 ( 1 ) ^ { 4 } + 4 ( 1 ) ^ { 3 } - 5 ( 1 ) ^ { 2 } + 7 ( 1 )$$

Evaluate

$$9$$

Solution Steps

Calculate 1 to the power of 4 and get 1.

$$3\times 1+4\times 1^{3}-5\times 1^{2}+7\times 1$$

Multiply 3 and 1 to get 3.

$$3+4\times 1^{3}-5\times 1^{2}+7\times 1$$

Calculate 1 to the power of 3 and get 1.

$$3+4\times 1-5\times 1^{2}+7\times 1$$

Multiply 4 and 1 to get 4.

$$3+4-5\times 1^{2}+7\times 1$$

Add 3 and 4 to get 7.

$$7-5\times 1^{2}+7\times 1$$

Calculate 1 to the power of 2 and get 1.

$$7-5\times 1+7\times 1$$

Multiply 5 and 1 to get 5.

$$7-5+7\times 1$$

Subtract 5 from 7 to get 2.

$$2+7\times 1$$

Multiply 7 and 1 to get 7.

$$2+7$$

Add 2 and 7 to get 9.

$$9$$

Factor

$$3^{2}$$