Solve 3(1*1/2)+(2-1/2)+(10-1/2)

$$3 ( 1 \cdot \frac { 1 } { 2 } ) + ( 2 - \frac { 1 } { 2 } ) + ( 10 - \frac { 1 } { 2 } )$$

Evaluate

$$\frac{25}{2}=12.5$$

Solution Steps

Multiply 3 and 1 to get 3.

$$3\times \frac{1}{2}+2-\frac{1}{2}+10-\frac{1}{2}$$

Multiply 3 and \frac{1}{2} to get \frac{3}{2}.

$$\frac{3}{2}+2-\frac{1}{2}+10-\frac{1}{2}$$

Convert 2 to fraction \frac{4}{2}.

$$\frac{3}{2}+\frac{4}{2}-\frac{1}{2}+10-\frac{1}{2}$$

Since \frac{3}{2} and \frac{4}{2} have the same denominator, add them by adding their numerators.

$$\frac{3+4}{2}-\frac{1}{2}+10-\frac{1}{2}$$

Add 3 and 4 to get 7.

$$\frac{7}{2}-\frac{1}{2}+10-\frac{1}{2}$$

Since \frac{7}{2} and \frac{1}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{7-1}{2}+10-\frac{1}{2}$$

Subtract 1 from 7 to get 6.

$$\frac{6}{2}+10-\frac{1}{2}$$

Divide 6 by 2 to get 3.

$$3+10-\frac{1}{2}$$

Add 3 and 10 to get 13.

$$13-\frac{1}{2}$$

Convert 13 to fraction \frac{26}{2}.

$$\frac{26}{2}-\frac{1}{2}$$

Since \frac{26}{2} and \frac{1}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{26-1}{2}$$

Subtract 1 from 26 to get 25.

$$\frac{25}{2}$$

Factor

$$\frac{5 ^ {2}}{2} = 12\frac{1}{2} = 12.5$$