Solve 3(-b-1)+6=6b

$$3 ( - b - 1 ) + 6 = 6 b$$

Solve for b

$$b=\frac{1}{3}\approx 0.333333333$$

Steps for Solving Linear Equation

Use the distributive property to multiply 3 by -b-1.

$$3\left(-b\right)-3+6=6b$$

Add -3 and 6 to get 3.

$$3\left(-b\right)+3=6b$$

Subtract 6b from both sides.

$$3\left(-b\right)+3-6b=0$$

Subtract 3 from both sides. Anything subtracted from zero gives its negation.

$$3\left(-b\right)-6b=-3$$

Multiply 3 and -1 to get -3.

$$-3b-6b=-3$$

Combine -3b and -6b to get -9b.

$$-9b=-3$$

Divide both sides by -9.

$$b=\frac{-3}{-9}$$

Reduce the fraction \frac{-3}{-9} to lowest terms by extracting and canceling out -3.

$$b=\frac{1}{3}$$