Solve 3(-4)^3+6(-4)^2

$$3 ( - 4 ) ^ { 3 } + 6 ( - 4 ) ^ { 2 }$$

Evaluate

$$-96$$

Solution Steps

Calculate -4 to the power of 3 and get -64.

$$3\left(-64\right)+6\left(-4\right)^{2}$$

Multiply 3 and -64 to get -192.

$$-192+6\left(-4\right)^{2}$$

Calculate -4 to the power of 2 and get 16.

$$-192+6\times 16$$

Multiply 6 and 16 to get 96.

$$-192+96$$

Add -192 and 96 to get -96.

$$-96$$

Factor

$$-96$$