Solve for x
x\geq 1
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-3x+1\leq \frac{-6}{3}
Divide both sides by 3. Since 3 is positive, the inequality direction remains the same.
-3x+1\leq -2
Divide -6 by 3 to get -2.
-3x\leq -2-1
Subtract 1 from both sides.
-3x\leq -3
Subtract 1 from -2 to get -3.
x\geq \frac{-3}{-3}
Divide both sides by -3. Since -3 is negative, the inequality direction is changed.
x\geq 1
Divide -3 by -3 to get 1.
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Limits
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