Solve 3(-2-2)^3+10(3)^2+6(8*1/2+3)

$$3 ( - 2 - 2 ) ^ { 3 } + 10 ( 3 ) ^ { 2 } + 6 ( 8 \cdot \frac { 1 } { 2 } + 3 )$$

Evaluate

$$-60$$

Solution Steps

Subtract 2 from -2 to get -4.

$$3\left(-4\right)^{3}+10\times 3^{2}+6\left(8\times \frac{1}{2}+3\right)$$

Calculate -4 to the power of 3 and get -64.

$$3\left(-64\right)+10\times 3^{2}+6\left(8\times \frac{1}{2}+3\right)$$

Multiply 3 and -64 to get -192.

$$-192+10\times 3^{2}+6\left(8\times \frac{1}{2}+3\right)$$

Calculate 3 to the power of 2 and get 9.

$$-192+10\times 9+6\left(8\times \frac{1}{2}+3\right)$$

Multiply 10 and 9 to get 90.

$$-192+90+6\left(8\times \frac{1}{2}+3\right)$$

Add -192 and 90 to get -102.

$$-102+6\left(8\times \frac{1}{2}+3\right)$$

Multiply 8 and \frac{1}{2} to get 4.

$$-102+6\left(4+3\right)$$

Add 4 and 3 to get 7.

$$-102+6\times 7$$

Multiply 6 and 7 to get 42.

$$-102+42$$

Add -102 and 42 to get -60.

$$-60$$

Factor

$$-60$$