Solve 3(-2)^3-4(-2)^3(4-2)-2

$$3 ( - 2 ) ^ { 3 } - 4 ( - 2 ) ^ { 3 } ( 4 - 2 ) - 2$$

Evaluate

$$38$$

Solution Steps

Calculate -2 to the power of 3 and get -8.

$$3\left(-8\right)-4\left(-2\right)^{3}\left(4-2\right)-2$$

Multiply 3 and -8 to get -24.

$$-24-4\left(-2\right)^{3}\left(4-2\right)-2$$

Calculate -2 to the power of 3 and get -8.

$$-24-4\left(-8\right)\left(4-2\right)-2$$

Multiply 4 and -8 to get -32.

$$-24-\left(-32\left(4-2\right)\right)-2$$

Subtract 2 from 4 to get 2.

$$-24-\left(-32\times 2\right)-2$$

Multiply -32 and 2 to get -64.

$$-24-\left(-64\right)-2$$

The opposite of -64 is 64.

$$-24+64-2$$

Add -24 and 64 to get 40.

$$40-2$$

Subtract 2 from 40 to get 38.

$$38$$

Factor

$$2\times 19$$