Solve 3(-2)^2-2(-3)^3+2sqrt{16}=

$$3 ( - 2 ) ^ { 2 } - 2 ( - 3 ) ^ { 3 } + 2 \sqrt { 16 } =$$

Evaluate

$$74$$

Solution Steps

Calculate -2 to the power of 2 and get 4.

$$3\times 4-2\left(-3\right)^{3}+2\sqrt{16}$$

Multiply 3 and 4 to get 12.

$$12-2\left(-3\right)^{3}+2\sqrt{16}$$

Calculate -3 to the power of 3 and get -27.

$$12-2\left(-27\right)+2\sqrt{16}$$

Multiply 2 and -27 to get -54.

$$12-\left(-54\right)+2\sqrt{16}$$

The opposite of -54 is 54.

$$12+54+2\sqrt{16}$$

Add 12 and 54 to get 66.

$$66+2\sqrt{16}$$

Calculate the square root of 16 and get 4.

$$66+2\times 4$$

Multiply 2 and 4 to get 8.

$$66+8$$

Add 66 and 8 to get 74.

$$74$$

Factor

$$2\times 37$$