Solve 3(7/3)^3+7x-7/3

$$3 ( \frac { 7 } { 3 } ) ^ { 3 } + 7 x - \frac { 7 } { 3 }$$

Evaluate

$$7x+\frac{322}{9}$$

Solution Steps

Calculate \frac{7}{3} to the power of 3 and get \frac{343}{27}.

$$3\times \frac{343}{27}+7x-\frac{7}{3}$$

Express 3\times \frac{343}{27} as a single fraction.

$$\frac{3\times 343}{27}+7x-\frac{7}{3}$$

Multiply 3 and 343 to get 1029.

$$\frac{1029}{27}+7x-\frac{7}{3}$$

Reduce the fraction \frac{1029}{27} to lowest terms by extracting and canceling out 3.

$$\frac{343}{9}+7x-\frac{7}{3}$$

Least common multiple of 9 and 3 is 9. Convert \frac{343}{9} and \frac{7}{3} to fractions with denominator 9.

$$\frac{343}{9}+7x-\frac{21}{9}$$

Since \frac{343}{9} and \frac{21}{9} have the same denominator, subtract them by subtracting their numerators.

$$\frac{343-21}{9}+7x$$

Subtract 21 from 343 to get 322.

$$\frac{322}{9}+7x$$

Factor

$$\frac{7\left(9x+46\right)}{9}$$

Solution Steps

Factor out \frac{7}{9}.

$$\frac{7\left(46+9x\right)}{9}$$

Consider 49+9x-3. Multiply and combine like terms.

$$9x+46$$

Rewrite the complete factored expression.

$$\frac{7\left(9x+46\right)}{9}$$