Solve for y
y=4
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3\left(4-4\right)+3y=12
Multiply both sides of the equation by 3.
3\times 0+3y=12
Subtract 4 from 4 to get 0.
0+3y=12
Multiply 3 and 0 to get 0.
3y=12
Anything plus zero gives itself.
y=\frac{12}{3}
Divide both sides by 3.
y=4
Divide 12 by 3 to get 4.
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