Solve 3x^4-4x^3-3x-1divx-1

$$3 { x }^{ 4 } -4 { x }^{ 3 } -3x-1 \div x-1$$

Evaluate

$$3x^{4}-4x^{3}-3x-1-\frac{1}{x}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply 3x^{4}-4x^{3}-3x-1 times \frac{x}{x}.

$$\frac{\left(3x^{4}-4x^{3}-3x-1\right)x}{x}-\frac{1}{x}$$

Since \frac{\left(3x^{4}-4x^{3}-3x-1\right)x}{x} and \frac{1}{x} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\left(3x^{4}-4x^{3}-3x-1\right)x-1}{x}$$

Do the multiplications in \left(3x^{4}-4x^{3}-3x-1\right)x-1.

$$\frac{3x^{5}-4x^{4}-3x^{2}-x-1}{x}$$

Factor

$$\frac{\left(3x^{2}+2x+1\right)\left(x^{3}-2x^{2}+x-1\right)}{x}$$