Solve for d
d=-\frac{14x^{2}+7x-25}{3x^{3}}
x\neq 0
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3x^{3}d+7x=25-14x^{2}
Subtract 14x^{2} from both sides.
3x^{3}d=25-14x^{2}-7x
Subtract 7x from both sides.
3x^{3}d=25-7x-14x^{2}
The equation is in standard form.
\frac{3x^{3}d}{3x^{3}}=\frac{25-7x-14x^{2}}{3x^{3}}
Divide both sides by 3x^{3}.
d=\frac{25-7x-14x^{2}}{3x^{3}}
Dividing by 3x^{3} undoes the multiplication by 3x^{3}.
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