Solve 3x^3-2x^2-18x-1divx+2

$$3 { x }^{ 3 } -2 { x }^{ 2 } -18x-1 \div x+2$$

Evaluate

$$3x^{3}-2x^{2}-18x+2-\frac{1}{x}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply 3x^{3}-2x^{2}-18x+2 times \frac{x}{x}.

$$\frac{\left(3x^{3}-2x^{2}-18x+2\right)x}{x}-\frac{1}{x}$$

Since \frac{\left(3x^{3}-2x^{2}-18x+2\right)x}{x} and \frac{1}{x} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\left(3x^{3}-2x^{2}-18x+2\right)x-1}{x}$$

Do the multiplications in \left(3x^{3}-2x^{2}-18x+2\right)x-1.

$$\frac{3x^{4}-2x^{3}-18x^{2}+2x-1}{x}$$

Factor

$$\frac{3x^{4}-2x^{3}-18x^{2}+2x-1}{x}$$