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Solve for x (complex solution)
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3x^{2}x^{2}-1+x^{2}\times 2=0
Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by x^{2}.
3x^{4}-1+x^{2}\times 2=0
To multiply powers of the same base, add their exponents. Add 2 and 2 to get 4.
3t^{2}+2t-1=0
Substitute t for x^{2}.
t=\frac{-2±\sqrt{2^{2}-4\times 3\left(-1\right)}}{2\times 3}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Substitute 3 for a, 2 for b, and -1 for c in the quadratic formula.
t=\frac{-2±4}{6}
Do the calculations.
t=\frac{1}{3} t=-1
Solve the equation t=\frac{-2±4}{6} when ± is plus and when ± is minus.
x=-\frac{\sqrt{3}}{3} x=\frac{\sqrt{3}}{3} x=-i x=i
Since x=t^{2}, the solutions are obtained by evaluating x=±\sqrt{t} for each t.
3x^{2}x^{2}-1+x^{2}\times 2=0
Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by x^{2}.
3x^{4}-1+x^{2}\times 2=0
To multiply powers of the same base, add their exponents. Add 2 and 2 to get 4.
3t^{2}+2t-1=0
Substitute t for x^{2}.
t=\frac{-2±\sqrt{2^{2}-4\times 3\left(-1\right)}}{2\times 3}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Substitute 3 for a, 2 for b, and -1 for c in the quadratic formula.
t=\frac{-2±4}{6}
Do the calculations.
t=\frac{1}{3} t=-1
Solve the equation t=\frac{-2±4}{6} when ± is plus and when ± is minus.
x=\frac{\sqrt{3}}{3} x=-\frac{\sqrt{3}}{3}
Since x=t^{2}, the solutions are obtained by evaluating x=±\sqrt{t} for positive t.