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x^{2}=\frac{27}{3}
Divide both sides by 3.
x^{2}=9
Divide 27 by 3 to get 9.
x^{2}-9=0
Subtract 9 from both sides.
\left(x-3\right)\left(x+3\right)=0
Consider x^{2}-9. Rewrite x^{2}-9 as x^{2}-3^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).
x=3 x=-3
To find equation solutions, solve x-3=0 and x+3=0.
x^{2}=\frac{27}{3}
Divide both sides by 3.
x^{2}=9
Divide 27 by 3 to get 9.
x=3 x=-3
Take the square root of both sides of the equation.
x^{2}=\frac{27}{3}
Divide both sides by 3.
x^{2}=9
Divide 27 by 3 to get 9.
x^{2}-9=0
Subtract 9 from both sides.
x=\frac{0±\sqrt{0^{2}-4\left(-9\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -9 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\left(-9\right)}}{2}
Square 0.
x=\frac{0±\sqrt{36}}{2}
Multiply -4 times -9.
x=\frac{0±6}{2}
Take the square root of 36.
x=3
Now solve the equation x=\frac{0±6}{2} when ± is plus. Divide 6 by 2.
x=-3
Now solve the equation x=\frac{0±6}{2} when ± is minus. Divide -6 by 2.
x=3 x=-3
The equation is now solved.