Solve 3x^2=156

$$3 { x }^{ 2 } =156$$

Solve for x

$$x=2\sqrt{13}\approx 7.211102551$$

$$x=-2\sqrt{13}\approx -7.211102551$$

Steps by Finding Square Root

Divide both sides by 3.

$$x^{2}=\frac{156}{3}$$

Divide 156 by 3 to get 52.

$$x^{2}=52$$

Take the square root of both sides of the equation.

$$x=2\sqrt{13} x=-2\sqrt{13}$$

Steps Using the Quadratic Formula

Divide both sides by 3.

$$x^{2}=\frac{156}{3}$$

Divide 156 by 3 to get 52.

$$x^{2}=52$$

Subtract 52 from both sides.

$$x^{2}-52=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -52 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-52\right)}}{2}$$

Square 0.

$$x=\frac{0±\sqrt{-4\left(-52\right)}}{2}$$

Multiply -4 times -52.

$$x=\frac{0±\sqrt{208}}{2}$$

Take the square root of 208.

$$x=\frac{0±4\sqrt{13}}{2}$$

Now solve the equation x=\frac{0±4\sqrt{13}}{2} when ± is plus.

$$x=2\sqrt{13}$$

Now solve the equation x=\frac{0±4\sqrt{13}}{2} when ± is minus.

$$x=-2\sqrt{13}$$

The equation is now solved.

$$x=2\sqrt{13} x=-2\sqrt{13}$$