Solve 3x^2+7-10=3(x+10/3)(x-1)

$$3 { x }^{ 2 } +7-10=3(x+ \frac{ 10 }{ 3 } )(x-1)$$

Solve for x

$$x=1$$

Steps for Solving Linear Equation

Subtract 10 from 7 to get -3.

$$3x^{2}-3=3\left(x+\frac{10}{3}\right)\left(x-1\right)$$

Use the distributive property to multiply 3 by x+\frac{10}{3}.

$$3x^{2}-3=\left(3x+10\right)\left(x-1\right)$$

Use the distributive property to multiply 3x+10 by x-1 and combine like terms.

$$3x^{2}-3=3x^{2}+7x-10$$

Subtract 3x^{2} from both sides.

$$3x^{2}-3-3x^{2}=7x-10$$

Combine 3x^{2} and -3x^{2} to get 0.

$$-3=7x-10$$

Swap sides so that all variable terms are on the left hand side.

$$7x-10=-3$$

Add 10 to both sides.

$$7x=-3+10$$

Add -3 and 10 to get 7.

$$7x=7$$

Divide both sides by 7.

$$x=\frac{7}{7}$$

Divide 7 by 7 to get 1.

$$x=1$$