Solve 3x^2*2=36

$$3 { x }^{ 2 } \times 2=36$$

Solve for x

$$x=\sqrt{6}\approx 2.449489743$$

$$x=-\sqrt{6}\approx -2.449489743$$

Steps by Finding Square Root

Multiply 3 and 2 to get 6.

$$6x^{2}=36$$

Divide both sides by 6.

$$x^{2}=\frac{36}{6}$$

Divide 36 by 6 to get 6.

$$x^{2}=6$$

Take the square root of both sides of the equation.

$$x=\sqrt{6} x=-\sqrt{6}$$

Steps Using the Quadratic Formula

Multiply 3 and 2 to get 6.

$$6x^{2}=36$$

Subtract 36 from both sides.

$$6x^{2}-36=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 6 for a, 0 for b, and -36 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\times 6\left(-36\right)}}{2\times 6}$$

Square 0.

$$x=\frac{0±\sqrt{-4\times 6\left(-36\right)}}{2\times 6}$$

Multiply -4 times 6.

$$x=\frac{0±\sqrt{-24\left(-36\right)}}{2\times 6}$$

Multiply -24 times -36.

$$x=\frac{0±\sqrt{864}}{2\times 6}$$

Take the square root of 864.

$$x=\frac{0±12\sqrt{6}}{2\times 6}$$

Multiply 2 times 6.

$$x=\frac{0±12\sqrt{6}}{12}$$

Now solve the equation x=\frac{0±12\sqrt{6}}{12} when ± is plus.

$$x=\sqrt{6}$$

Now solve the equation x=\frac{0±12\sqrt{6}}{12} when ± is minus.

$$x=-\sqrt{6}$$

The equation is now solved.

$$x=\sqrt{6} x=-\sqrt{6}$$