Solve 3n^2-48n-2=0

$$3 { n }^{ 2 } -48n-2 = 0$$

Solve for n

$$n=\frac{\sqrt{582}}{3}+8\approx 16.041558721$$

$$n=-\frac{\sqrt{582}}{3}+8\approx -0.041558721$$

Steps Using the Quadratic Formula

All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.

$$3n^{2}-48n-2=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 3 for a, -48 for b, and -2 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$n=\frac{-\left(-48\right)±\sqrt{\left(-48\right)^{2}-4\times 3\left(-2\right)}}{2\times 3}$$

Square -48.

$$n=\frac{-\left(-48\right)±\sqrt{2304-4\times 3\left(-2\right)}}{2\times 3}$$

Multiply -4 times 3.

$$n=\frac{-\left(-48\right)±\sqrt{2304-12\left(-2\right)}}{2\times 3}$$

Multiply -12 times -2.

$$n=\frac{-\left(-48\right)±\sqrt{2304+24}}{2\times 3}$$

Add 2304 to 24.

$$n=\frac{-\left(-48\right)±\sqrt{2328}}{2\times 3}$$

Take the square root of 2328.

$$n=\frac{-\left(-48\right)±2\sqrt{582}}{2\times 3}$$

The opposite of -48 is 48.

$$n=\frac{48±2\sqrt{582}}{2\times 3}$$

Multiply 2 times 3.

$$n=\frac{48±2\sqrt{582}}{6}$$

Now solve the equation n=\frac{48±2\sqrt{582}}{6} when ± is plus. Add 48 to 2\sqrt{582}.

$$n=\frac{2\sqrt{582}+48}{6}$$

Divide 48+2\sqrt{582} by 6.

$$n=\frac{\sqrt{582}}{3}+8$$

Now solve the equation n=\frac{48±2\sqrt{582}}{6} when ± is minus. Subtract 2\sqrt{582} from 48.

$$n=\frac{48-2\sqrt{582}}{6}$$

Divide 48-2\sqrt{582} by 6.

$$n=-\frac{\sqrt{582}}{3}+8$$

The equation is now solved.

$$n=\frac{\sqrt{582}}{3}+8 n=-\frac{\sqrt{582}}{3}+8$$

Steps for Completing the Square

Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.

$$3n^{2}-48n-2=0$$

Add 2 to both sides of the equation.

$$3n^{2}-48n-2-\left(-2\right)=-\left(-2\right)$$

Subtracting -2 from itself leaves 0.

$$3n^{2}-48n=-\left(-2\right)$$

Subtract -2 from 0.

$$3n^{2}-48n=2$$

Divide both sides by 3.

$$\frac{3n^{2}-48n}{3}=\frac{2}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$n^{2}+\left(-\frac{48}{3}\right)n=\frac{2}{3}$$

Divide -48 by 3.

$$n^{2}-16n=\frac{2}{3}$$

Divide -16, the coefficient of the x term, by 2 to get -8. Then add the square of -8 to both sides of the equation. This step makes the left hand side of the equation a perfect square.

$$n^{2}-16n+\left(-8\right)^{2}=\frac{2}{3}+\left(-8\right)^{2}$$

Square -8.

$$n^{2}-16n+64=\frac{2}{3}+64$$

Add \frac{2}{3} to 64.

$$n^{2}-16n+64=\frac{194}{3}$$

Factor n^{2}-16n+64. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.

$$\left(n-8\right)^{2}=\frac{194}{3}$$

Take the square root of both sides of the equation.

$$\sqrt{\left(n-8\right)^{2}}=\sqrt{\frac{194}{3}}$$

Simplify.

$$n-8=\frac{\sqrt{582}}{3} n-8=-\frac{\sqrt{582}}{3}$$

Add 8 to both sides of the equation.

$$n=\frac{\sqrt{582}}{3}+8 n=-\frac{\sqrt{582}}{3}+8$$