Solve 3a^2*(-2ab)*(3ab^2)

$$3 { a }^{ 2 } \times (-2ab) \times (3a { b }^{ 2 } )$$

Evaluate

$$-18b^{3}a^{4}$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 2 and 1 to get 3.

$$3a^{3}\left(-2\right)b\times 3ab^{2}$$

To multiply powers of the same base, add their exponents. Add 3 and 1 to get 4.

$$3a^{4}\left(-2\right)b\times 3b^{2}$$

To multiply powers of the same base, add their exponents. Add 1 and 2 to get 3.

$$3a^{4}\left(-2\right)b^{3}\times 3$$

Multiply 3 and -2 to get -6.

$$-6a^{4}b^{3}\times 3$$

Multiply -6 and 3 to get -18.

$$-18a^{4}b^{3}$$

Differentiate w.r.t. b

$$-54b^{2}a^{4}$$