Solve 3left(1+2right)^-2+9^-1+12^0

$$3 { \left(1+2 \right) }^{ -2 } + { 9 }^{ -1 } + { 12 }^{ 0 }$$

Evaluate

$$\frac{13}{9}\approx 1.444444444$$

Solution Steps

Add 1 and 2 to get 3.

$$3\times 3^{-2}+9^{-1}+12^{0}$$

Calculate 3 to the power of -2 and get \frac{1}{9}.

$$3\times \frac{1}{9}+9^{-1}+12^{0}$$

Multiply 3 and \frac{1}{9} to get \frac{1}{3}.

$$\frac{1}{3}+9^{-1}+12^{0}$$

Calculate 9 to the power of -1 and get \frac{1}{9}.

$$\frac{1}{3}+\frac{1}{9}+12^{0}$$

Add \frac{1}{3} and \frac{1}{9} to get \frac{4}{9}.

$$\frac{4}{9}+12^{0}$$

Calculate 12 to the power of 0 and get 1.

$$\frac{4}{9}+1$$

Add \frac{4}{9} and 1 to get \frac{13}{9}.

$$\frac{13}{9}$$

Factor

$$\frac{13}{3 ^ {2}} = 1\frac{4}{9} = 1.4444444444444444$$