Solve 3{left(1/3right)}^2+1/3m-2=0

$$3 { \left( \frac{ 1 }{ 3 } \right) }^{ 2 } + \frac{ 1 }{ 3 } m-2 = 0$$

Solve for m

$$m=5$$

Steps for Solving Linear Equation

Calculate \frac{1}{3} to the power of 2 and get \frac{1}{9}.

$$3\times \frac{1}{9}+\frac{1}{3}m-2=0$$

Multiply 3 and \frac{1}{9} to get \frac{3}{9}.

$$\frac{3}{9}+\frac{1}{3}m-2=0$$

Reduce the fraction \frac{3}{9} to lowest terms by extracting and canceling out 3.

$$\frac{1}{3}+\frac{1}{3}m-2=0$$

Convert 2 to fraction \frac{6}{3}.

$$\frac{1}{3}+\frac{1}{3}m-\frac{6}{3}=0$$

Since \frac{1}{3} and \frac{6}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{1-6}{3}+\frac{1}{3}m=0$$

Subtract 6 from 1 to get -5.

$$-\frac{5}{3}+\frac{1}{3}m=0$$

Add \frac{5}{3} to both sides. Anything plus zero gives itself.

$$\frac{1}{3}m=\frac{5}{3}$$

Multiply both sides by 3, the reciprocal of \frac{1}{3}.

$$m=\frac{5}{3}\times 3$$

Cancel out 3 and 3.

$$m=5$$