Solve 3varepsilon-(4-2x)=x+8

$$3 \varepsilon - ( 4 - 2 x ) = x + 8$$

Solve for x

$$x=12-3\epsilon$$

Solution Steps

To find the opposite of 4-2x, find the opposite of each term.

$$3\epsilon -4+2x=x+8$$

Subtract x from both sides.

$$3\epsilon -4+2x-x=8$$

Combine 2x and -x to get x.

$$3\epsilon -4+x=8$$

Subtract 3\epsilon from both sides.

$$-4+x=8-3\epsilon$$

Add 4 to both sides.

$$x=8-3\epsilon +4$$

Add 8 and 4 to get 12.

$$x=12-3\epsilon$$

Solve for ε

$$\epsilon =-\frac{x}{3}+4$$

Steps for Solving Linear Equation

To find the opposite of 4-2x, find the opposite of each term.

$$3\epsilon -4+2x=x+8$$

Add 4 to both sides.

$$3\epsilon +2x=x+8+4$$

Add 8 and 4 to get 12.

$$3\epsilon +2x=x+12$$

Subtract 2x from both sides.

$$3\epsilon =x+12-2x$$

Combine x and -2x to get -x.

$$3\epsilon =-x+12$$

The equation is in standard form.

$$3\epsilon =12-x$$

Divide both sides by 3.

$$\frac{3\epsilon }{3}=\frac{12-x}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$\epsilon =\frac{12-x}{3}$$

Divide -x+12 by 3.

$$\epsilon =-\frac{x}{3}+4$$