Solve 3*36^2+sqrt{12}=

$$3 \times 36 ^ { 2 } + \sqrt { 12 } =$$

Evaluate

$$2\left(\sqrt{3}+1944\right)\approx 3891.464101615$$

Solution Steps

Calculate 36 to the power of 2 and get 1296.

$$3\times 1296+\sqrt{12}$$

Multiply 3 and 1296 to get 3888.

$$3888+\sqrt{12}$$

Factor 12=2^{2}\times 3. Rewrite the square root of the product \sqrt{2^{2}\times 3} as the product of square roots \sqrt{2^{2}}\sqrt{3}. Take the square root of 2^{2}.

$$3888+2\sqrt{3}$$