Solve 3*2div9+3*6-9div5+81

$$3 \times 2 \div 9 + 3 \times 6 - 9 \div 5 + 81$$

Evaluate

$$\frac{1468}{15}\approx 97.866666667$$

Solution Steps

Multiply 3 and 2 to get 6.

$$\frac{6}{9}+3\times 6-\frac{9}{5}+81$$

Reduce the fraction \frac{6}{9} to lowest terms by extracting and canceling out 3.

$$\frac{2}{3}+3\times 6-\frac{9}{5}+81$$

Multiply 3 and 6 to get 18.

$$\frac{2}{3}+18-\frac{9}{5}+81$$

Convert 18 to fraction \frac{54}{3}.

$$\frac{2}{3}+\frac{54}{3}-\frac{9}{5}+81$$

Since \frac{2}{3} and \frac{54}{3} have the same denominator, add them by adding their numerators.

$$\frac{2+54}{3}-\frac{9}{5}+81$$

Add 2 and 54 to get 56.

$$\frac{56}{3}-\frac{9}{5}+81$$

Least common multiple of 3 and 5 is 15. Convert \frac{56}{3} and \frac{9}{5} to fractions with denominator 15.

$$\frac{280}{15}-\frac{27}{15}+81$$

Since \frac{280}{15} and \frac{27}{15} have the same denominator, subtract them by subtracting their numerators.

$$\frac{280-27}{15}+81$$

Subtract 27 from 280 to get 253.

$$\frac{253}{15}+81$$

Convert 81 to fraction \frac{1215}{15}.

$$\frac{253}{15}+\frac{1215}{15}$$

Since \frac{253}{15} and \frac{1215}{15} have the same denominator, add them by adding their numerators.

$$\frac{253+1215}{15}$$

Add 253 and 1215 to get 1468.

$$\frac{1468}{15}$$

Factor

$$\frac{2 ^ {2} \cdot 367}{3 \cdot 5} = 97\frac{13}{15} = 97.86666666666666$$