Solve 3*(1/2)^3-4*(1/2)^2

$$3 \times ( \frac { 1 } { 2 } ) ^ { 3 } - 4 \times ( \frac { 1 } { 2 } ) ^ { 2 }$$

Evaluate

$$-\frac{5}{8}=-0.625$$

Solution Steps

Calculate \frac{1}{2} to the power of 3 and get \frac{1}{8}.

$$3\times \frac{1}{8}-4\times \left(\frac{1}{2}\right)^{2}$$

Multiply 3 and \frac{1}{8} to get \frac{3}{8}.

$$\frac{3}{8}-4\times \left(\frac{1}{2}\right)^{2}$$

Calculate \frac{1}{2} to the power of 2 and get \frac{1}{4}.

$$\frac{3}{8}-4\times \frac{1}{4}$$

Cancel out 4 and 4.

$$\frac{3}{8}-1$$

Convert 1 to fraction \frac{8}{8}.

$$\frac{3}{8}-\frac{8}{8}$$

Since \frac{3}{8} and \frac{8}{8} have the same denominator, subtract them by subtracting their numerators.

$$\frac{3-8}{8}$$

Subtract 8 from 3 to get -5.

$$-\frac{5}{8}$$

Factor

$$-\frac{5}{8} = -0.625$$