Solve 3*49/36-7*7/6+2

$$3 \times \frac { 49 } { 36 } - \frac { 7 \times 7 } { 6 } + 2$$

Evaluate

$$-\frac{25}{12}\approx -2.083333333$$

Solution Steps

Express 3\times \frac{49}{36} as a single fraction.

$$\frac{3\times 49}{36}-\frac{7\times 7}{6}+2$$

Multiply 3 and 49 to get 147.

$$\frac{147}{36}-\frac{7\times 7}{6}+2$$

Reduce the fraction \frac{147}{36} to lowest terms by extracting and canceling out 3.

$$\frac{49}{12}-\frac{7\times 7}{6}+2$$

Multiply 7 and 7 to get 49.

$$\frac{49}{12}-\frac{49}{6}+2$$

Least common multiple of 12 and 6 is 12. Convert \frac{49}{12} and \frac{49}{6} to fractions with denominator 12.

$$\frac{49}{12}-\frac{98}{12}+2$$

Since \frac{49}{12} and \frac{98}{12} have the same denominator, subtract them by subtracting their numerators.

$$\frac{49-98}{12}+2$$

Subtract 98 from 49 to get -49.

$$-\frac{49}{12}+2$$

Convert 2 to fraction \frac{24}{12}.

$$-\frac{49}{12}+\frac{24}{12}$$

Since -\frac{49}{12} and \frac{24}{12} have the same denominator, add them by adding their numerators.

$$\frac{-49+24}{12}$$

Add -49 and 24 to get -25.

$$-\frac{25}{12}$$

Factor

$$-\frac{25}{12} = -2\frac{1}{12} = -2.0833333333333335$$