Solve 3*1/2(1/2-12/3)=27/8

$$3 \times \frac { 1 } { 2 } ( \frac { 1 } { 2 } - \frac { 12 } { 3 } ) = \frac { 27 } { 8 }$$

Verify

Solution Steps

Multiply 3 and \frac{1}{2} to get \frac{3}{2}.

$$\frac{3}{2}\left(\frac{1}{2}-\frac{12}{3}\right)=\frac{27}{8}$$

Divide 12 by 3 to get 4.

$$\frac{3}{2}\left(\frac{1}{2}-4\right)=\frac{27}{8}$$

Convert 4 to fraction \frac{8}{2}.

$$\frac{3}{2}\left(\frac{1}{2}-\frac{8}{2}\right)=\frac{27}{8}$$

Since \frac{1}{2} and \frac{8}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{3}{2}\times \frac{1-8}{2}=\frac{27}{8}$$

Subtract 8 from 1 to get -7.

$$\frac{3}{2}\left(-\frac{7}{2}\right)=\frac{27}{8}$$

Multiply \frac{3}{2} times -\frac{7}{2} by multiplying numerator times numerator and denominator times denominator.

$$\frac{3\left(-7\right)}{2\times 2}=\frac{27}{8}$$

Do the multiplications in the fraction \frac{3\left(-7\right)}{2\times 2}.

$$\frac{-21}{4}=\frac{27}{8}$$

Fraction \frac{-21}{4} can be rewritten as -\frac{21}{4} by extracting the negative sign.

$$-\frac{21}{4}=\frac{27}{8}$$

Least common multiple of 4 and 8 is 8. Convert -\frac{21}{4} and \frac{27}{8} to fractions with denominator 8.

$$-\frac{42}{8}=\frac{27}{8}$$

Compare -\frac{42}{8} and \frac{27}{8}.

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