Solve 3*6+6/-4--4^2

$$3 \times 6+ \frac{ 6 }{ -4 } - { -4 }^{ 2 }$$

Evaluate

$$\frac{1}{2}=0.5$$

Solution Steps

Multiply 3 and 6 to get 18.

$$18+\frac{6}{-4}-\left(-4\right)^{2}$$

Reduce the fraction \frac{6}{-4} to lowest terms by extracting and canceling out 2.

$$18-\frac{3}{2}-\left(-4\right)^{2}$$

Convert 18 to fraction \frac{36}{2}.

$$\frac{36}{2}-\frac{3}{2}-\left(-4\right)^{2}$$

Since \frac{36}{2} and \frac{3}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{36-3}{2}-\left(-4\right)^{2}$$

Subtract 3 from 36 to get 33.

$$\frac{33}{2}-\left(-4\right)^{2}$$

Calculate -4 to the power of 2 and get 16.

$$\frac{33}{2}-16$$

Convert 16 to fraction \frac{32}{2}.

$$\frac{33}{2}-\frac{32}{2}$$

Since \frac{33}{2} and \frac{32}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{33-32}{2}$$

Subtract 32 from 33 to get 1.

$$\frac{1}{2}$$

Factor

$$\frac{1}{2} = 0.5$$