Solve 3*3(4-2*3)+2*3(3*3-5)

$$3 \times 3(4-2 \times 3)+2 \times 3(3 \times 3-5)$$

Evaluate

$$6$$

Solution Steps

Multiply 3 and 3 to get 9. Multiply 2 and 3 to get 6.

$$9\left(4-2\times 3\right)+6\left(3\times 3-5\right)$$

Multiply 2 and 3 to get 6.

$$9\left(4-6\right)+6\left(3\times 3-5\right)$$

Subtract 6 from 4 to get -2.

$$9\left(-2\right)+6\left(3\times 3-5\right)$$

Multiply 9 and -2 to get -18.

$$-18+6\left(3\times 3-5\right)$$

Multiply 3 and 3 to get 9.

$$-18+6\left(9-5\right)$$

Subtract 5 from 9 to get 4.

$$-18+6\times 4$$

Multiply 6 and 4 to get 24.

$$-18+24$$

Add -18 and 24 to get 6.

$$6$$

Factor

$$2\times 3$$