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6+|-4|-\left(\sqrt{2}\right)^{0}
Multiply 3 and 2 to get 6.
6+4-\left(\sqrt{2}\right)^{0}
The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -4 is 4.
10-\left(\sqrt{2}\right)^{0}
Add 6 and 4 to get 10.
10-1
Calculate \sqrt{2} to the power of 0 and get 1.
9
Subtract 1 from 10 to get 9.