Solve 3*-1^2-2-1^2*-4-(-4^2

$$3 \times - { 1 }^{ 2 } -2- { 1 }^{ 2 } \times -4-(- { 4 }^{ 2 }$$

Evaluate

$$15$$

Solution Steps

Calculate 1 to the power of 2 and get 1.

$$3\left(-1\right)-2-1^{2}\left(-4\right)-\left(-4^{2}\right)$$

Multiply 3 and -1 to get -3.

$$-3-2-1^{2}\left(-4\right)-\left(-4^{2}\right)$$

Subtract 2 from -3 to get -5.

$$-5-1^{2}\left(-4\right)-\left(-4^{2}\right)$$

Calculate 1 to the power of 2 and get 1.

$$-5-1\left(-4\right)-\left(-4^{2}\right)$$

Multiply 1 and -4 to get -4.

$$-5-\left(-4\right)-\left(-4^{2}\right)$$

The opposite of -4 is 4.

$$-5+4-\left(-4^{2}\right)$$

Add -5 and 4 to get -1.

$$-1-\left(-4^{2}\right)$$

Calculate 4 to the power of 2 and get 16.

$$-1-\left(-16\right)$$

The opposite of -16 is 16.

$$-1+16$$

Add -1 and 16 to get 15.

$$15$$

Factor

$$3\times 5$$