Solve 3*{left(1/8right)}^2+3*1/8+3

$$3 \times { \left( \frac{ 1 }{ 8 } \right) }^{ 2 } +3 \times \frac{ 1 }{ 8 } +3$$

Evaluate

$$\frac{219}{64}=3.421875$$

Solution Steps

Calculate \frac{1}{8} to the power of 2 and get \frac{1}{64}.

$$3\times \frac{1}{64}+3\times \frac{1}{8}+3$$

Multiply 3 and \frac{1}{64} to get \frac{3}{64}.

$$\frac{3}{64}+3\times \frac{1}{8}+3$$

Multiply 3 and \frac{1}{8} to get \frac{3}{8}.

$$\frac{3}{64}+\frac{3}{8}+3$$

Least common multiple of 64 and 8 is 64. Convert \frac{3}{64} and \frac{3}{8} to fractions with denominator 64.

$$\frac{3}{64}+\frac{24}{64}+3$$

Since \frac{3}{64} and \frac{24}{64} have the same denominator, add them by adding their numerators.

$$\frac{3+24}{64}+3$$

Add 3 and 24 to get 27.

$$\frac{27}{64}+3$$

Convert 3 to fraction \frac{192}{64}.

$$\frac{27}{64}+\frac{192}{64}$$

Since \frac{27}{64} and \frac{192}{64} have the same denominator, add them by adding their numerators.

$$\frac{27+192}{64}$$

Add 27 and 192 to get 219.

$$\frac{219}{64}$$

Factor

$$\frac{3 \cdot 73}{2 ^ {6}} = 3\frac{27}{64} = 3.421875$$