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\frac{3\times 2\sqrt{2}}{-2\sqrt{3}}
Factor 8=2^{2}\times 2. Rewrite the square root of the product \sqrt{2^{2}\times 2} as the product of square roots \sqrt{2^{2}}\sqrt{2}. Take the square root of 2^{2}.
\frac{6\sqrt{2}}{-2\sqrt{3}}
Multiply 3 and 2 to get 6.
\frac{3\sqrt{2}}{-\sqrt{3}}
Cancel out 2 in both numerator and denominator.
\frac{-3\sqrt{2}}{\sqrt{3}}
Cancel out -1 in both numerator and denominator.
\frac{-3\sqrt{2}\sqrt{3}}{\left(\sqrt{3}\right)^{2}}
Rationalize the denominator of \frac{-3\sqrt{2}}{\sqrt{3}} by multiplying numerator and denominator by \sqrt{3}.
\frac{-3\sqrt{2}\sqrt{3}}{3}
The square of \sqrt{3} is 3.
\frac{-3\sqrt{6}}{3}
To multiply \sqrt{2} and \sqrt{3}, multiply the numbers under the square root.
-\sqrt{6}
Cancel out 3 and 3.