Solve for x
x=16
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3\sqrt{x}-12-\left(-12\right)=-\left(-12\right)
Add 12 to both sides of the equation.
3\sqrt{x}=-\left(-12\right)
Subtracting -12 from itself leaves 0.
3\sqrt{x}=12
Subtract -12 from 0.
\frac{3\sqrt{x}}{3}=\frac{12}{3}
Divide both sides by 3.
\sqrt{x}=\frac{12}{3}
Dividing by 3 undoes the multiplication by 3.
\sqrt{x}=4
Divide 12 by 3.
x=16
Square both sides of the equation.
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