Solve 3sqrt{81}-2*(1/2)^2+4^-1

$$3 \sqrt { 81 } - 2 \cdot ( \frac { 1 } { 2 } ) ^ { 2 } + 4 ^ { - 1 }$$

Evaluate

$$\frac{107}{4}=26.75$$

Solution Steps

Calculate the square root of 81 and get 9.

$$3\times 9-2\times \left(\frac{1}{2}\right)^{2}+4^{-1}$$

Multiply 3 and 9 to get 27.

$$27-2\times \left(\frac{1}{2}\right)^{2}+4^{-1}$$

Calculate \frac{1}{2} to the power of 2 and get \frac{1}{4}.

$$27-2\times \frac{1}{4}+4^{-1}$$

Multiply 2 and \frac{1}{4} to get \frac{1}{2}.

$$27-\frac{1}{2}+4^{-1}$$

Subtract \frac{1}{2} from 27 to get \frac{53}{2}.

$$\frac{53}{2}+4^{-1}$$

Calculate 4 to the power of -1 and get \frac{1}{4}.

$$\frac{53}{2}+\frac{1}{4}$$

Add \frac{53}{2} and \frac{1}{4} to get \frac{107}{4}.

$$\frac{107}{4}$$

Factor

$$\frac{107}{2 ^ {2}} = 26\frac{3}{4} = 26.75$$