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3\times 2\sqrt{2}+\sqrt{0}-\sqrt{4}
Factor 8=2^{2}\times 2. Rewrite the square root of the product \sqrt{2^{2}\times 2} as the product of square roots \sqrt{2^{2}}\sqrt{2}. Take the square root of 2^{2}.
6\sqrt{2}+\sqrt{0}-\sqrt{4}
Multiply 3 and 2 to get 6.
6\sqrt{2}+0-\sqrt{4}
Calculate the square root of 0 and get 0.
6\sqrt{2}+0-2
Calculate the square root of 4 and get 2.
6\sqrt{2}-2
Subtract 2 from 0 to get -2.