Solve 3sqrt{2x-1}=sqrt{8}

$$3 \sqrt { 2 x - 1 } = \sqrt { 8 }$$

Solve for x

$$x=\frac{17}{18}\approx 0.944444444$$

Steps for Solving Radical Equations

Divide both sides by 3.

$$\frac{3\sqrt{2x-1}}{3}=\frac{2\sqrt{2}}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$\sqrt{2x-1}=\frac{2\sqrt{2}}{3}$$

Square both sides of the equation.

$$2x-1=\frac{8}{9}$$

Add 1 to both sides of the equation.

$$2x-1-\left(-1\right)=\frac{8}{9}-\left(-1\right)$$

Subtracting -1 from itself leaves 0.

$$2x=\frac{8}{9}-\left(-1\right)$$

Subtract -1 from \frac{8}{9}.

$$2x=\frac{17}{9}$$

Divide both sides by 2.

$$\frac{2x}{2}=\frac{\frac{17}{9}}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$x=\frac{\frac{17}{9}}{2}$$

Divide \frac{17}{9} by 2.

$$x=\frac{17}{18}$$