Solve for x
x=8
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3\sqrt{2x}-3-\left(-3\right)=9-\left(-3\right)
Add 3 to both sides of the equation.
3\sqrt{2x}=9-\left(-3\right)
Subtracting -3 from itself leaves 0.
3\sqrt{2x}=12
Subtract -3 from 9.
\frac{3\sqrt{2x}}{3}=\frac{12}{3}
Divide both sides by 3.
\sqrt{2x}=\frac{12}{3}
Dividing by 3 undoes the multiplication by 3.
\sqrt{2x}=4
Divide 12 by 3.
2x=16
Square both sides of the equation.
\frac{2x}{2}=\frac{16}{2}
Divide both sides by 2.
x=\frac{16}{2}
Dividing by 2 undoes the multiplication by 2.
x=8
Divide 16 by 2.
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