Solve for b
b\geq \frac{13}{3}
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9\leq 3b-\left(1\times 3+1\right)
Multiply both sides of the equation by 3. Since 3 is positive, the inequality direction remains the same.
9\leq 3b-\left(3+1\right)
Multiply 1 and 3 to get 3.
9\leq 3b-4
Add 3 and 1 to get 4.
3b-4\geq 9
Swap sides so that all variable terms are on the left hand side. This changes the sign direction.
3b\geq 9+4
Add 4 to both sides.
3b\geq 13
Add 9 and 4 to get 13.
b\geq \frac{13}{3}
Divide both sides by 3. Since 3 is positive, the inequality direction remains the same.
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