Solve 3left(p-qright)+9=23

$$3 \left( p-q \right) +9 = 23$$

Solve for p

$$p = \frac{14}{3} = 4\frac{2}{3} = 4.666666666666667$$

Steps for Solving Linear Equation

Use the distributive property to multiply 3 by p-q.

$$3p-3q+9=23$$

Add 3q to both sides.

$$3p+9=23+3q$$

Subtract 9 from both sides.

$$3p=23+3q-9$$

Subtract 9 from 23 to get 14.

$$3p=14+3q$$

The equation is in standard form.

$$3p=3q+14$$

Divide both sides by 3.

$$\frac{3p}{3}=\frac{3q+14}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$p=\frac{3q+14}{3}$$

Divide 14+3q by 3.

$$p=q+\frac{14}{3}$$

Solve for q

$$q = -\frac{14}{3} = -4\frac{2}{3} = -4.666666666666667$$

Steps for Solving Linear Equation

Use the distributive property to multiply 3 by p-q.

$$3p-3q+9=23$$

Subtract 3p from both sides.

$$-3q+9=23-3p$$

Subtract 9 from both sides.

$$-3q=23-3p-9$$

Subtract 9 from 23 to get 14.

$$-3q=14-3p$$

Divide both sides by -3.

$$\frac{-3q}{-3}=\frac{14-3p}{-3}$$

Dividing by -3 undoes the multiplication by -3.

$$q=\frac{14-3p}{-3}$$

Divide 14-3p by -3.

$$q=p-\frac{14}{3}$$