Solve 32/7+83/4-64/5=

$$3 \frac{ 2 }{ 7 } +8 \frac{ 3 }{ 4 } -6 \frac{ 4 }{ 5 } =$$

Evaluate

$$\frac{733}{140}\approx 5.235714286$$

Solution Steps

Multiply 3 and 7 to get 21.

$$\frac{21+2}{7}+\frac{8\times 4+3}{4}-\frac{6\times 5+4}{5}$$

Add 21 and 2 to get 23.

$$\frac{23}{7}+\frac{8\times 4+3}{4}-\frac{6\times 5+4}{5}$$

Multiply 8 and 4 to get 32.

$$\frac{23}{7}+\frac{32+3}{4}-\frac{6\times 5+4}{5}$$

Add 32 and 3 to get 35.

$$\frac{23}{7}+\frac{35}{4}-\frac{6\times 5+4}{5}$$

Least common multiple of 7 and 4 is 28. Convert \frac{23}{7} and \frac{35}{4} to fractions with denominator 28.

$$\frac{92}{28}+\frac{245}{28}-\frac{6\times 5+4}{5}$$

Since \frac{92}{28} and \frac{245}{28} have the same denominator, add them by adding their numerators.

$$\frac{92+245}{28}-\frac{6\times 5+4}{5}$$

Add 92 and 245 to get 337.

$$\frac{337}{28}-\frac{6\times 5+4}{5}$$

Multiply 6 and 5 to get 30.

$$\frac{337}{28}-\frac{30+4}{5}$$

Add 30 and 4 to get 34.

$$\frac{337}{28}-\frac{34}{5}$$

Least common multiple of 28 and 5 is 140. Convert \frac{337}{28} and \frac{34}{5} to fractions with denominator 140.

$$\frac{1685}{140}-\frac{952}{140}$$

Since \frac{1685}{140} and \frac{952}{140} have the same denominator, subtract them by subtracting their numerators.

$$\frac{1685-952}{140}$$

Subtract 952 from 1685 to get 733.

$$\frac{733}{140}$$

Factor

$$\frac{733}{2 ^ {2} \cdot 5 \cdot 7} = 5\frac{33}{140} = 5.235714285714286$$